Question

a man bought a cow and a calf for $990 paying 8 times as much for the cow as for the calf what was the cost of each​

Answer 1

Let x = the cost of the calf.  The cow costs 8 times as much, so it costs 8x.  Together they cost $990:

 

   x + 8x = $990

    9x=990

    x=990/9

    x=110

so the calf cost=110

and cow cost =880

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Answer 2

Answer:

let the cp of calf be X

and the cp of cow be 8 times from calf i.e 8x

X+8x=990

=9x=990. (cp=cost price)

=X=990/9

X=110

now the cp of calf be X so, X=110

cp of cow is 8x=8*110=880

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