Math, asked by shakshikataria15, 7 months ago

.A man bought a horse and a
camel. He sold horse at 20%
profit and camel at 10% loss and
in this way he made neither profit
nor loss. Had he sold the horse
at 5% loss and camel at 5% profit
he would have earned 600
rupees. Find the cost price of
horse and camel.​

Answers

Answered by Anonymous
0

The amount paid by him was Rs. 400 for the horse and Rs. 200 for the cart.

Let's assume that the cost of the horse be

Rs. "x and the cost of the cart be Rs. "y"

According to the first case of thequestion,

we have10% of loss in selling the horse

20% ofgain in selling the cartTO X= TyX= 2y

(Also, according to the second case of

thequestion, we have5% of loss in selling

horse is Rs. 10 morethan the 5% gain in

selling the cartTOX]-10 [TOO yl

y]5x 1000 = 5y10y 1000 5y . [substituting

fromn5y 1000y-20oNow, substituting the

value of y in eq. ().we getX 2yX 220OX=

400Thus, the CP of the Horse is Rs. 400

y]5x 1000 5y10y 1000 5y. [substituting

fromn5y 1000y-20oNow, substituting the

value of y in eq. ().we getX = 2yX = 2200X=

400

Thus, the CP of the Horse is Rs. 400and the

CP of the Cart is Rs. 200.

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