A man bought a horse and a cart. If he sold the horse at 10 % loss and the cart at
20 % gain, he would not lose anything; but if he sold the horse at 5% loss and the cart
at 5% gain, he would lose Rs. 10 in the bargain. The amount paid by him was
Rs._______ for the horse and Rs.________ for the cart.
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Hi friend,
Let X be the cost of horse
Y be the cost of the cart.
According to question,
10% of loss in selling horse = 20% of gain in selling the cart.
=> (10/100)*X = (20*100)*Y
=> X = 2y --------------(1)
Also,
5% of loss in selling horse is 10 more than the 5% gain in selling the cart.
=> (5/100) *X – 10 = (5/100) *Y
=> 5X – 1000 = 5Y
=> 10Y – 1000 = 5Y (Using equation 1)
=> 5Y = 1000
=> Y =200.
=> X = 2Y = 2*200 = 400.
Hence,
CP of Horse = Rs. 400.
CP of the Cart = Rs. 200.
Hope it helps!
Let X be the cost of horse
Y be the cost of the cart.
According to question,
10% of loss in selling horse = 20% of gain in selling the cart.
=> (10/100)*X = (20*100)*Y
=> X = 2y --------------(1)
Also,
5% of loss in selling horse is 10 more than the 5% gain in selling the cart.
=> (5/100) *X – 10 = (5/100) *Y
=> 5X – 1000 = 5Y
=> 10Y – 1000 = 5Y (Using equation 1)
=> 5Y = 1000
=> Y =200.
=> X = 2Y = 2*200 = 400.
Hence,
CP of Horse = Rs. 400.
CP of the Cart = Rs. 200.
Hope it helps!
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