Question

A man bought a house and a cart. If he sold the horse at 10% loss and

the cart at 20% gain he would not lose anything. But if he sold the
horse at 5% loss and the cart at 5% gain, he would lose Rs.10 in the bargain. What did he pay for each ?​

Answer 1

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Let X be the cost of horse

Y be the cost of the cart.

            

                        According to question,

10% of loss in selling horse = 20% of gain in selling the cart.

  => (10/100)×X = (20×100)×Y

 

=> X = 2y --------------(1)

Also,

5% of loss in selling horse is 10 more than the 5% gain in selling the cart.

=> (5/100) ×X – 10 = (5/100) ×Y

=> 5X – 1000 = 5Y

=> 10Y – 1000 = 5Y                        

 (Using equation 1)

=> 5Y = 1000

=> Y =200.

=> X = 2Y = 2×200 = 400.

Hence,

CP of Horse = Rs. 400.

CP of the Cart = Rs. 200

Answer 2

Answer:

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$\huge\bigstar\pink{answer:-}⋆answer:−$

Let X be the cost of horse

Y be the cost of the cart.

According to question,

10% of loss in selling horse = 20% of gain in selling the cart.

• => (10/100)×X = (20×100)×Y

• => X = 2y --------------(1)

Also,

• 5% of loss in selling horse is 10 more than the 5% gain in selling the cart.

• => (5/100) ×X – 10 = (5/100) ×Y

• => 5X – 1000 = 5Y

• => 10Y – 1000 = 5Y

(Using equation 1)

• => 5Y = 1000

• => Y =200.

• => X = 2Y = 2×200 = 400.

Hence,

• CP of Horse = Rs. 400.

• CP of the Cart = Rs. 200

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