a man bought a plot of land for Rupee 150000 and a car for Rupees 180000 at the same time the price of the plot of land grows uniformly at the rate of 25% while the price of the car depresses by 20% per annum if the man sells the plot and land as well as the car after 3 years , what will be his profit or loss?
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A man buys a plot of land at Rs.360000.He sells one third of the plot at a loss of 20℅.Again he sells two third of the plot left at the profit of 25℅.At what price should he sell the remaining plot in order to get a profit of 10℅ on the whole.
Asked by triloksingh945315 | 24th Nov, 2018, 08:18: AM
Expert Answer:
1/3 of plot,i.e., Rs.1,20,000 sold out for a loss of 20%. Hence selling price = 120000 - [ 120000×(20/100) ] = Rs. 96000 ..........(1)
2/3 of left plot area = [ 1 - (1/3) ]×(2/3) = 4/9 part of initial plot area
cost value of 4/9 plot area = 360000 × (4/9) = Rs. 1,60,000
if 4/9 part of plot is sold for 25% profit, then selling price = 160000 + [ 160000 × (25/100) ] = Rs. 200000 .....................(2)
cost value of left out plot = [ 1 - (1/3) - (4/9) ]×360000 = Rs.80000
total selling price till now = Rs. ( 96000 + 200000 ) = Rs. 2,96,000
overall selling price for the profit of 10% = 360000 + [ 360000×(10/100) ] = Rs. 3,96,000
Hence the left out plot has to be sold for Rs. ( 3,96,000 - 2,96,000) = Rs. 1,00,000