a man bought a plot of land for rupees 160000 and a car for rupees 180000 at the same time the price of the plot of land grows uniformly at the rate of 25 % per annum will the price of the car depreciates by 20% per annum if the main cells a plot of land as well as a car after three years what will be his profit or loss
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Answers
cost of plot is 160000
the price of the plot of land grows uniformly at the rate of 25% per annum
the price of the plot after first year= 160000+(160000×25/100) = 200000
the price of the plot after 2 year= 200000+(200000×25/100) = 250000
the price of the plot after 3 year=
250000+(250000×25/100)=312500
selling price of the plot = 312500
cost price of the car = 180000
cost price of the car after 1 year = 180000-(180000×20/100) = 144000
cost price of the car after 2 year = 144000-(144000×20/100) = 11200
cost price of the car after 3 year 11200-(11200×20/100) = 8960
selling price of the car = 8960
cost price of both plot and car is = 160000+180000 = 340000
selling price of both plot and car is = 312500+8960 = 321460
loss = cost price - selling price
loss = 340000 - 321460
loss = 18540
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