Question

A man bought a rope of length 10m.He cut it into three parts.
1 part-5 1/2-mixed fraction
2 part-35/11-mixed fraction
How much of rope is left?

Answer 1

Answer:

1  1/22 of the rope if left

Step-by-step explanation:

1st part:

10 - 5 ½ = 4 ½

Therefore, the 1st part of the rope is 4 ½.

2nd part:

4 ½ - 3 5/11

3 5/11 = 38/11 (3 x 11 + 5)

So, we must find  4 ½ - 38/11

Which is, 23/22

As mixed fraction it is = 1 1/22(mixed fraction)

So,

1  1/22 of the rope if left

HOPE IT HELPS!