Math, asked by pawanawachar93, 6 months ago

A man bought a rope of length10m.He cut two peices - one of length 5 1/2 m and the other of length 3 5/11 m.How much of the rope is left?

Answers

Answered by aditiyadav02
9

Answer:

23/22 m = 1 1/22 m

Step-by-step explanation:

Total rope length = 10 m

Total length of pieces = 5 1/2 m + 3 5/11 m

                                     = 11/2 m + 38/11 m

                                     = 121/22 m + 76/22 m

                                     = 197/22 m

Length of rope left = 10 m -  197/22 m

                               = 220/22 m - 197/22 m

                               = 23/22 m

                               = 1 1/22 m

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