Question

a man bought certain no of oranges out of which 13 percent were rotten .but he gave 75 perent of the remaining in charity and still has 522 oranges find how many. he has bought but have answer simply pls urgent​

Answer 1

Answer:

He buys x oranges at 20 for Rs.60/-

Each orange will cost 60/20 or Rs.3/-

So cost price of this variety of orange =3x

Similarly he buys x (same quantity) at 30 for Rs.60/-. So cost per orange 60/30 or Rs.2/-

So CP of the 2nd variety = 2x

Total quantity of both varieties :3x+2x = 5x

Total cost of both varieties = Rs.120/-

5x = Rs.120, x = 24

So his average CP is he buys 24 oranges for Rs.60/- or CP per orange =60/24 or 5/2

He sells at 25 oranges for Rs 60 or SP per orange = 60/25 or 12/5

Loss = CP-SP = 5/2-12/5=1/10

Loss Percent = loss/CP x 100

1/10 ÷5/2 x 100 = 1/10×2/5×100 = 4% loss.

Answer 2

Answer:

He bought 4350 oranges I think

Step-by-step explanation:

Let us consider total no. of oranges as 'x'

75%x = gave to charity

13%x = rotten

75%+13%=88%

Left oranges = 12%

12%x= 522

12/100 x= 522

3/25 x =522 (Divide 12 and 100 by 4)

x = 522 X 25 / 3 ( Cross multiplication)

x = 174 X 25 ( Divide 522 and 3 by 3)

x= 4350