A man bought pens of varied costs for 1125. The price of the pens were 20
and *25. If he has a total of 50 pens, then the number of pens that costed 20
is
Answers
Answered by
0
Answer:
No of pens which cost 20 = x
No of pens which cost 25 = y
20x + 25y = 1125 (1)
x+y = 50
20x + 20y = 1000 (2)
Subtract (2) from (1),
5y = 125
y = 25
x =25
=> the number of pens which cost 20 = 25
Answered by
1
Let :
- Number of pens that cost 25 = x
- Number of pens that cost 20 = y
Given :
- Total number of pens = 50
- Total cost of pens = 1125
Solution :
- Total number of pen = number of pen that cost 25 + number of pen that cost 20
=> Total number of pen = x+ y
also given that total number of pen = 50
from this we get
x + y = 50 equation 1
- Total cost of pen = 25x + 20y
also total cost = 1125
from this we get
25x + 20y = 1125 equation 2
Multiplying equation 1 by 20 and subtracting from equation 2
we get
=> 25x + 20y - 20(x+y) = 1125 - 20(50)
=> 25x + 20y - 20x - 20y = 1125 - 1000
=> 5x = 125
=> x = 125/5
=> x = 25
putting value of x in equation 1 , we get;
=> x + y = 50
=> 25 + y = 50
=> y = 50-25
=> y = 25
ANSWER :
- Number of pens that cost 20 = 25
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