Question

A man bought some apples of which 13 percent of then were rotten. He sold 75 percent of the balance and was left with 261 apples. How many apples did he have originally?

Answer 1

Out of some apples bought by man 13% were rotten, 75% were sold off the balance and left with 261 then the no. of apples he originally had is 1200.

Step-by-step explanation:

Let originally the no. of apples be “x”.

It is given 13% of the original no. of apples were rotten

So, the % of apples left with the man now will be = 100 – 13 = 87%

Also given that, out of 87%, 75% of the apples were sold by the man

So, the final % of the apples left will be = 25% of 87%

But the final balance left is given as 261 apples.

Therefore, we can write the eq. as,

$\frac{25}{100} * \frac{87}{100}$ * x = 261

⇒ x = $\frac{261 * 100 * 100}{25 * 87}$

⇒ x = $\frac{2610000}{2175}$

⇒ x = 1200

Thus, the man originally had 1200 apples.

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