A man bought some bananas of Rupees 4 at the rate of 10 and sold them for rupees 4 at rate of 8 What will be Profit or loss percentage?
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Answer:
Purchase cost per banana=10/6=5/3 and sold at 6/4=3/2 hence loss per banana is 5/3–3/2=10–9/6=1/6 Rs hence loss % is ((1/6)/(5/3))*100= 3*100/30=10%
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CP of 1 banana = 6 10
Rs.=1.667Rs.
SP of 4 banana =6Rs.
SP of 1 banana = 4 6
Rs.=1.5Rs.
Since CP of 1 banana greater than SP of 1 banana.
Therefore,
Loss%= CP
CP−SP×100
= 1.667
1.667−1.5 ×100=10%
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