A man bought some pens for ₹60. If the price of each pen had been ₹1 less, he would have got 3 pens more, how much did each pen cost him (in ₹) originally?
Answers
Step-by-step explanation:
Answer
AnswerLet the number of books be = x.
AnswerLet the number of books be = x.Total cost of the books = Rs. 60.
AnswerLet the number of books be = x.Total cost of the books = Rs. 60.∴ Cost of each book =Rs.
AnswerLet the number of books be = x.Total cost of the books = Rs. 60.∴ Cost of each book =Rs. x60
AnswerLet the number of books be = x.Total cost of the books = Rs. 60.∴ Cost of each book =Rs. x60 If the number of books is (x + 5), then the cost of each book = Rs.
AnswerLet the number of books be = x.Total cost of the books = Rs. 60.∴ Cost of each book =Rs. x60 If the number of books is (x + 5), then the cost of each book = Rs. x+5 60
60 Difference in cost is one rupee = Cost of each book when number of books is (x) - Cost of each book when number of books is (x + 5)
60 Difference in cost is one rupee = Cost of each book when number of books is (x) - Cost of each book when number of books is (x + 5)x
60 Difference in cost is one rupee = Cost of each book when number of books is (x) - Cost of each book when number of books is (x + 5)x60
60 Difference in cost is one rupee = Cost of each book when number of books is (x) - Cost of each book when number of books is (x + 5)x60 −
60 Difference in cost is one rupee = Cost of each book when number of books is (x) - Cost of each book when number of books is (x + 5)x60 − x+5 60 =1
60 =1x(x+5)60(x+5)−60x =1
60 =1x(x+5)60(x+5)−60x =1x 2 +5x60x+300−60x =1
+5x60x+300−60x =1x 2 +5x=300
+5x60x+300−60x =1x 2 +5x=300x 2 +5x−300=0
+5x60x+300−60x =1x 2 +5x=300x 2 +5x−300=0x 2 +20x−15x−300=0
+5x60x+300−60x =1x 2 +5x=300x 2 +5x−300=0x 2 +20x−15x−300=0x(x+20)−15(x+20)=0
+5x60x+300−60x =1x 2 +5x=300x 2 +5x−300=0x 2 +20x−15x−300=0x(x+20)−15(x+20)=0(x+20)(x−15)=0
+5x60x+300−60x =1x 2 +5x=300x 2 +5x−300=0x 2 +20x−15x−300=0x(x+20)−15(x+20)=0(x+20)(x−15)=0x+20=0 or x−15=0
+5x60x+300−60x =1x 2 +5x=300x 2 +5x−300=0x 2 +20x−15x−300=0x(x+20)−15(x+20)=0(x+20)(x−15)=0x+20=0 or x−15=0∴x=−20 or x=15
+5x60x+300−60x =1x 2 +5x=300x 2 +5x−300=0x 2 +20x−15x−300=0x(x+20)−15(x+20)=0(x+20)(x−15)=0x+20=0 or x−15=0∴x=−20 or x=15∴ Number of books = x = 15
+5x60x+300−60x =1x 2 +5x=300x 2 +5x−300=0x 2 +20x−15x−300=0x(x+20)−15(x+20)=0(x+20)(x−15)=0x+20=0 or x−15=0∴x=−20 or x=15∴ Number of books = x = 15Number of books cannot be negative. Hence, -20 is rejected.
+5x60x+300−60x =1x 2 +5x=300x 2 +5x−300=0x 2 +20x−15x−300=0x(x+20)−15(x+20)=0(x+20)(x−15)=0x+20=0 or x−15=0∴x=−20 or x=15∴ Number of books = x = 15Number of books cannot be negative. Hence, -20 is rejected.∴ Cost of each book =
+5x60x+300−60x =1x 2 +5x=300x 2 +5x−300=0x 2 +20x−15x−300=0x(x+20)−15(x+20)=0(x+20)(x−15)=0x+20=0 or x−15=0∴x=−20 or x=15∴ Number of books = x = 15Number of books cannot be negative. Hence, -20 is rejected.∴ Cost of each book = x60 = 15
= 1560 =Rs.4