Question

a man bought tho computers for Rs 45000.he sold one at a loss of 5% and the other at a profit of 5%.If the selling price of each set is same,find the cost price of each set.

Answer 1

Solution :-

Let us assume that, Cost Price of First computer is Rs.x .

we have given that, he bought two computers for Rs.45000 .

So,

→ CP(cost Price) of second computer is = Rs.(45000 - x)

Now, it is given that, he Sold one at a loss of 5% and the other at a profit of 5%. and the selling price of each set is same .

So,

→ SP of First computer = SP of 2nd computer .

→ {CP * (100 - Loss%) / 100} = {CP * (100 + Profit%) / 100}

100 will be cancel from both side of denominator, and putting values than , we get,

→ x * (100 - 5) = (45000 - x) * (100 + 5)

→ 95x = 45000 * 105 - 105x

→ 95x + 105x = 45000 * 105

→ 200x = 45000 * 105

Divide by 100 both sides ,

→ 2x = 450 * 105

Divide by 2 both sides now,

→ x = 225 * 105

→ x = Rs.23,625

Hence,

→ Cost Price of First computer = x = Rs.23,625 (Ans.)

→ Cost Price of second computer = (45000 - x) = 45000 - 23625 = Rs.21,375 (Ans.)

Answer 2

Given.

• Cost of two computers is Rs. 45000
• One computer is sold at 5% loss and the other at 5% profit.
• Selling price is same for each computer.

To find.

• The cost of each computer

Solution.

Step 1. Assumption step

Let the cost of one computer be Rs. x

∴ the cost of the other one be Rs. (45000 - x)

Step 2. Selling price of the 1st computer

Cost of one computer is Rs. x

It is sold at 5% loss.

∴ selling price is Rs. x * (1 - 5/100) = Rs. 95x/100

Step 3. Selling price of the 2nd computer

Cost of the other is Rs. (45000 - x)

It is sold at 5% profit.

∴ selling price is Rs. (45000 - x) * (1 + 5/100)

= Rs. (45000 - x) * 105/100

Step 4. Equating selling prices

By the given condition, selling price is same for each computer.

Then, 95x/100 = (45000 - x) * 105/100

or, 95x/100 = (45000 * 105)/100 - 105x/100

or, 95x/100 + 105x/100 = 47250

or, (95 + 105) * x/100 = 47250

or, 200x/100 = 47250

or, 2x = 47250

or, x = 47250/2

or, x = 23625

Step 5. Finding cost prices

Cost price of one computer is Rs. 23625

Cost price of the other computer is

Rs. (45000 - 23265)

= Rs. 21735

Answer:

• Cost price of the first set is Rs. 23625 .
• Cost price of the second set is Rs. 21375 .