Question

A man bought two airticle for Rs3120 He sold one of them at a loss of 15% anfd other at a gain of 36%. He then found each airticle was being sold for the same price. Find cost price of each airticle.

Answer 1

Answer:

1920, 1200

Step-by-step explanation:

Let the CP of Article 1 = x

Therefore CP of article 2 = 3120 - x

CP1 * (100 - loss%) / 100 = SP1 and

Therefore x * (100 - 15) / 100 = SP1

SP1 = 0.85x

Also

CP * (100 + Profit%) / 100 = SP

Therefore (3120 - x) * (100 + 36) / 100 = SP2

SP2 = 1.36 * (3120 - x)

SP2 = 4243.2 - 1.36x

Since SP1 = SP2

Therefore 0.85x = 4243.2 - 1.36x

Solving for x, we get 1.36x + 0.85x = 4243.2

2.21x = 4243.2

x = 1920

Therefore CP of article 1 = 1920 and

CP of article 2 = 3120 - 1920 = 1200