Math, asked by midstories2, 6 months ago

A man bought two bikes for ₹ 1,85,600. By selling one at a loss of 15% and the other at a profit of 12% he found that the selling price of the Frist bike is more than second bike by ₹10,000. Find the CP of each​

Answers

Answered by Anonymous
2

Answer:

Let the first bike be B

1

and the second bike be B

2

Let x and y be the C.P of B

1

and B

2

respectively.

According to the question,x+y=185600 ......(1)

S.P of bike B

1

=C.P of B

1

+15% of C.P of B

1

⇒S.P of B

1

=x−

100

15x

=

100

100x−15x

=

100

85x

Also,S.P of bike B

2

=C.P of B

2

+15% of C.P of B

2

⇒S.P of B

1

=y+

100

15y

=

100

100y+15y

=

100

115y

Given that S.P B

1

=10000+S.P of B

2

100

85x

=10000+

100

115y

⇒85x=1000000+115y

⇒85x−115y=1000000

⇒17x−23y=200000 ........(2)

Solving equations (1) and (2) simultaneously, we get

(1)⇒y=185600−x

⇒17x−23(185600−x)=200000

⇒17x+23x=200000+4268800‬=4468800‬

⇒40x=4468800‬

∴x=

40

4468800‬

=111720‬

Substituting x=111720 in (1) we get

y=185600−111720=73,880‬

Hence the C.P of first bike is Rs.111720 and of second bike is Rs.73880

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