A man bought two bikes for ₹ 1,85,600. By selling one at a loss of 15% and the other at a profit of 12% he found that the selling price of the Frist bike is more than second bike by ₹10,000. Find the CP of each
Answers
Answer:
Let the first bike be B
1
and the second bike be B
2
Let x and y be the C.P of B
1
and B
2
respectively.
According to the question,x+y=185600 ......(1)
S.P of bike B
1
=C.P of B
1
+15% of C.P of B
1
⇒S.P of B
1
=x−
100
15x
=
100
100x−15x
=
100
85x
Also,S.P of bike B
2
=C.P of B
2
+15% of C.P of B
2
⇒S.P of B
1
=y+
100
15y
=
100
100y+15y
=
100
115y
Given that S.P B
1
=10000+S.P of B
2
⇒
100
85x
=10000+
100
115y
⇒85x=1000000+115y
⇒85x−115y=1000000
⇒17x−23y=200000 ........(2)
Solving equations (1) and (2) simultaneously, we get
(1)⇒y=185600−x
⇒17x−23(185600−x)=200000
⇒17x+23x=200000+4268800=4468800
⇒40x=4468800
∴x=
40
4468800
=111720
Substituting x=111720 in (1) we get
y=185600−111720=73,880
Hence the C.P of first bike is Rs.111720 and of second bike is Rs.73880