Math, asked by lonely18, 11 months ago

A man bought two computers for Rs.45000. He sold one at a loss of 5% and the other at a profit of 5%. If the selling price of each set is same, find the cost price of each set.


Correct answer is
Rs.23625 and Rs.21375

Please solve it with full method

Answers

Answered by SonuKaler
31

Answer:

cost of one computer is RS 23625

cost of another computer is RS 21375

Attachments:
Answered by amitnrw
10

Given : A man bought two computers for Rs.45000. He sold one at a loss of 5% and the other at a profit of 5% .  the selling price of each set is same

To Find : the cost price of each set.

Solution:

CP are 100x   & 100y

100x + (5/100)100x  = 105x

100y - (5/100)100y  = 95y

105x  = 95y

=> 21x = 19y

100x + 100y  = 45000

=> x + y = 450

x + y = 450

21x = 19y

=> 21x = 19(450 - x)

=> 40x  = 19 * 450

=> 4x = 19 * 45

=> 4x * 25 = 19 * 45 * 25

=> 100x = 25 * 19 * 45

=> 100x = 21375 Rs

100x + 100y  = 45000

=> 100y = 23625 Rs

Cost price are Rs.23625 and Rs.21375

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