Question

A man bought two cycles for rs1040. He sold one at loss of 15% and other at a profit of 36% and then he found that each cycle was sold for the same price. Find the C.P. Of each cycle

Answer 1

CP of one bicycle = 1040 ÷ 2 = Rs.520

SP of first cycle = 520 x 85/100 = Rs.442

SP of second cycle = 520 x 136/100 = Rs.707.20

If there is no profit then

CP of one bicycle = Rs.442

CP of second bicycle = Rs.707.20

Answer 2

Given :

A man bought two cycles for rs1040. He sold one at loss of 15% and other at a profit of 36% and then he found that each cycle was sold for the same price.

To Find :

Find the C.P. Of each cycle

Solution:

Case 1 :

Let CP of 1 cycle be x

Loss% = 15%

$SP = \frac{CP(100-L\%)}{100}\\SP=\frac{x(100-15)}{100}\\SP=0.85x$

Case 2:

CP of cycle 2 = 1040-x

Profit% = 36%

$SP=\frac{CP(100+P\%)}{100}\\SP=\frac{(1040-x)(100+36)}{100}\\SP=1.36(1040-x)$

Now we are given that  he found that each cycle was sold for the same price.

So, 0.85x=1.36(1040-x)

x=640

Cp of cycle 1 = Rs.640

CP of cycle 2 = 1040-640=400

Hence The CP of cycle 1 is Rs.640 and CP of cylce 2 is Rs.400