Question

A man bought two cycles for rupees 1040 he sold one at a loss of 15% and other at a profit of 36 % and then he found that each cycle was sold for the same price find the CP of each cycle

Answer 1

Answer:

CP of 1st cycle is 400,CP of 2nd cycle is 640

Step-by-step explanation:

Let,

CP1 and SP1 for 1st  cycle

CP2 and SP2 for 2nd cycle

Given,

each cycle was sold for the same price

SP1=SP2

Let CP1=x

     CP2=(1040-x)

We know that SP=((100+gain)/100)*CP

SP1=(100+gain)/100*x

SP2=(100-loss)/100*(1040-x)

(136/100)*x=(85/100)*(1040-x)

136x=88400-85x

221x=88400

x=400 (CP1)

1040-400=640(CP2)