Math, asked by nagasri17763, 11 months ago

a man bought two goats for 2018 he go he sold one at a loss of 20% and other a profit of 44% if each would was sold at the same price the cost price of the code which was sold at a loss was​

Answers

Answered by VishnuPriya2801
2

Answer:

cost of first goat=2018

loss% = 20%

selling price =100-20/100×2018

selling price = 80/100×2018=1614.4

cost price of second goat=2018

profit%=44%

selling price =100+44/100×2018=313.92

total CP=4036

total SP=1928.32

loss = Cp-Sp=4036-1928.32 =2107.68

Answered by jyothimeesala
1

Step-by-step explanation:

Cost price of two goats is Rs.1008.

⇒ 80% of cost price of first goat = 144% of cost price of second goat.

⇒ cost price of first goat : cost price of second goat = 144:80=9:5

⇒ Cost price of first goat=

9+5

9 ×1008= rs 648

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