A Man Bought Two Goats For Rs 1008.He Sold One At A Loss Of 20%&Amp; Other At A Profit Of 44%.If Each Goat Was Sold At The Same Price,The Cost Price Of The Goat Which Was Sold At Loss,Was.....?
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Answer:
Rs 648 is the cost price of the goat which is sold at 10% loss.
Step-by-step explanation:
Let cost price of one goat be X.
Let cost price of the other goat be Y.
Now ,X+Y = Rs. 1008
Now one goat is sold at loss of 20% and other goat is sold at 44% profit.
Let the first goat having cost price X is sold at 20%loss.
If both the selling price is same, then,
((100-20) /100) X = ((100+44) /100) Y
0.8X = 1.44Y
X=(1.44/0.8) Y.
Putting the value of X in first equation,
(1.44/0.8) Y+Y = 1008
Y(0.8+1.44) /0.8 =1008
Y = (1008×0.8) /(0.8+1.44) =360.
X=(1008-360) = Rs 648.
The cost price of the goat which is sold at 20%loss is Rs 648.
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