a man bought two old scooters for rs. 24000. he sold one scooter at a gain of 6%. ao one at a loss of 12%. the dealer gained nothing from his outlet find its C.P of each scooter
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Let the C.P. of the 1st scooter = Rs. x.
Then, C.P. of the 2nd scooter = Rs. (18000−x)
S.P. of 1st scooter = Rs. x×100125= Rs. 45x
S.P. of 2nd scooter = Rs. (18000−x)×10080 = Rs. 54(18000−x)
Since Mohan neither gains nor loses, his total S.P. = Total C.P.
⇒45x+54(18000−x)=18000
⇒45x−54x=18000−14400=3600
⇒2025x−16x=3600⇒9x=3600×20
⇒x=93600×20=8000
∴ C.P. of 1st scooter = Rs. 800
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