Math, asked by amiteshapnowvt9j, 1 year ago

A man bought two TV sets for Rs 42500.He sold one at a loss of 10% and other at a profit of 10%. If the selling price of each TV set is same determine the cost price of each set.

Answers

Answered by saira4unaseeb

Let c.p of first tv is "x" then c.p of other things is (42500-x)
Loss=10%= 90%of "x"
Profit=10%= 110% of(42500-x)
According To question,
90%of "x" = 110% of (42500-x)

Solve above eaquation and find the value of "x" it will give you price of first tv and when you substract it from 42500 it will give the price of second one.

Anudipa: Let the cost price of one TV be x. So the cost price of another is 42500-x.

The man solds one tv at a loss of 10%.
So the selling price = x-0.1x= 0.9x

The another tv is sold at a profit of 10%.
Selling price
=(42500-x)+{(42500-x)×0.1(42500-x)}
=46750-1.1x

a/q 0.9x=46750-1.1x
=> 2x=46750
=> x=23375

And the cost price of another tv
= 42500-x
=42500-23375
=19125

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