A man bought two TV sets for Rs. 42500. He sold one at a loss of 10% and other at a profit of
10%. If the selling price of each TV set is same, find the cost price of each set.
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Answers
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Answer:
Cost Price of First set = ₹19125
Cost Price of Second set = ₹23375
Step-by-step explanation:
Given : A man bought two TV sets for Rs 42500.He sold one at a loss of 10% and other at a profit of 10%.
To find : If the selling price of each TV set is same determine the cost price of each set?
Solution :
Total cost of 2 TV sets = ₹42500
Let the cost of First TV set be x
Then,
Cost of second TV set = ₹(42500-x)
Selling price of First TV set is
\begin{gathered}SP_1= x+10\% \text{ of } x\\\\SP_1= \frac{110x}{100}\end{gathered}
SP
1
=x+10% of x
SP
1
=
100
110x
Selling price of second TV set is
\begin{gathered}SP_2= 42500-x-10\% \text{ of }(42500-x)\\\\SP_2= \frac{90(42500-x)}{100}\end{gathered}
SP
2
=42500−x−10% of (42500−x)
SP
2
=
100
90(42500−x)
S.P of First TV set = S.P of Second TV set
\frac{110x}{100}=\frac{90(42500-x)}{100}
100
110x
=
100
90(42500−x)
11x=90(42500-x)11x=90(42500−x)
11x=382500-9x11x=382500−9x
20x=38250020x=382500
x=19125x=19125
Therefore, Cost Price of First set = ₹19125
Cost Price of Second set = ₹23375
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