Question

A man boys two books at 410 and sells both at the same price. One gives him a profit of 15% and a other a loss of 10%.the cost price of both book is

Answer 1

Hey there!!

2 books, selling price = 410 rupees

cost price of first book = x

cost price of 2nd book = y

Gain% formula = [( selling price - cost price ) ÷ cost price] × 100

Loss% formula = [( cost price - selling price ) ÷ cost price] × 100

First book :

cost price = x

selling price = 410

Gain% = 15

15 = [( 410 - x ) ÷ x )] × 100

15x = 41000 - 100x

100x + 15x = 41000

115x = 41000

x = 41000 ÷ 115

x = 356.52 rupees

Cost price of first book = 356,.52 rupees

Second book :

Cost price = y

selling price = 410

Loss% = 10

10 = [( x - 410 ) ÷ x )] × 100

10x = 100x - 41000

41000 = 90x

x = 41000 ÷ 90

x = 455.55

Cost price of second book = 455.55

Hope my answer helps!

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