A man brought a certain number of orange out of which 13% were rotten he gave 75% of the remaining in charity and still has 522 oranges left find how many had he brought ?
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Answered by
182
let no.of oranges bought=100
then percentage of oranges rotten=13%
then remaining oranges=100-13% of 100 i.e.=87
percentage given to charity out of left oranges=75% of 87 i.e.=21.75
by unitary method 100 - 21.75 then if 522 are left then no.of oranges bought=522*100/21.75 i.e.=2400
then percentage of oranges rotten=13%
then remaining oranges=100-13% of 100 i.e.=87
percentage given to charity out of left oranges=75% of 87 i.e.=21.75
by unitary method 100 - 21.75 then if 522 are left then no.of oranges bought=522*100/21.75 i.e.=2400
Answered by
34
Answer:
2400 oranges
Step-by-step explanation:
let no.of oranges bought=100
then percentage of oranges rotten=13%
then remaining oranges=100-13% of 100 i.e.=87
percentage given to charity out of left oranges=75% of 87 i.e.=21.75
by unitary method 100 - 21.75 then if 522 are left then no.of oranges bought=522*100/21.75 i.e.=2400
Hope it helps!!
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