Math, asked by sristisingh1908, 6 months ago

A man brought an article for, ruppes X and sold it for ruppes 16. if the loss was X percent find the cost price of the article.​

Answers

Answered by charusatija0702
1

Step-by-step explanation:

cp of article= X

Sp of article= 16 rs.

Loss = X-16

Loss percent= (X-16 )/ X ×100

X= (X-16)/X × 100

X= (100X-1600)/X

(X)sqr 2 = 100X - 1600

(X) sqr2 - 100X + 1600= 0

(X)sqr2 -80X-20X+1600=0

(X-80)(X-20)=0

X=80,20

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