Question

A man brought his scooter at rate of 18000 by making profit 20pa. Then find cost price

Answer 1

Answer:

10,000

Step-by-step explanation:

Let the C.P. of the 1  

st

 scooter = Rs. x.  

Then, C.P. of the 2  

nd

 scooter = Rs. (18000−x)

S.P. of 1  

st

 scooter = Rs. x×  

100

125

​  

= Rs.  

4

5x

​  

 

S.P. of 2  

nd

 scooter = Rs. (18000−x)×  

100

80

​  

 = Rs.  

5

4

​  

(18000−x)

Since Mohan neither gains nor loses, his total S.P. = Total C.P.

⇒  

4

5x

​  

+  

5

4

​  

(18000−x)=18000

⇒  

4

5x

​  

−  

5

4x

​  

=18000−14400=3600

⇒  

20

25x−16x

​  

=3600⇒9x=3600×20

⇒x=  

9

3600×20

​  

=8000

∴ C.P. of 1  

st

 scooter = Rs. 8000

C.P. of 2  

nd

 scooter = Rs. 10,000