Math, asked by gsaikedar7610, 1 year ago

A man brought some watermelons to town and sold them. he sold 1/2 more than 1/2 of what he brought and e was left with one melon. how many melons did he bring to town? ans: 3

Answers

Answered by PanditAbhishek
6
Solution -   
                     Let number of watermelons man brought = x
                    1/2 more than 1/2 of x = 1/2 + x/2 
                     Number of watermelons left = 1
                           x- (x/2 +1/2) = 1
                           x/2 - 1/2 = 1
                            x/2 = 3/2 
                            x = 3    Answer 
Answered by Golda
4
Solution :-

Let the total number of watermelons brought to town by the man be x

He sold 1/2 more 1/2 of what he brought = 1/2 more than 1/2 of x 

Number of watermelons left with him = 1

Now, according to the question.

⇒ x - (1/2 of x + 1/2) = 1

⇒ x/1 - x/2 - 1/2 = 1 

⇒ x/2 = 1 + 1/2

⇒ x/2 = 3/2

⇒ 2x = 3*2

⇒ 2x = 6

⇒ x = 6/2

⇒ x = 3

So, he brought 3 watermelons to the town.

Answer.
Similar questions