A man brought some watermelons to town and sold them. he sold 1/2 more than 1/2 of what he brought and e was left with one melon. how many melons did he bring to town? ans: 3
Answers
Answered by
6
Solution -
Let number of watermelons man brought = x
1/2 more than 1/2 of x = 1/2 + x/2
Number of watermelons left = 1
x- (x/2 +1/2) = 1
x/2 - 1/2 = 1
x/2 = 3/2
x = 3 Answer
Let number of watermelons man brought = x
1/2 more than 1/2 of x = 1/2 + x/2
Number of watermelons left = 1
x- (x/2 +1/2) = 1
x/2 - 1/2 = 1
x/2 = 3/2
x = 3 Answer
Answered by
4
Solution :-
Let the total number of watermelons brought to town by the man be x
He sold 1/2 more 1/2 of what he brought = 1/2 more than 1/2 of x
Number of watermelons left with him = 1
Now, according to the question.
⇒ x - (1/2 of x + 1/2) = 1
⇒ x/1 - x/2 - 1/2 = 1
⇒ x/2 = 1 + 1/2
⇒ x/2 = 3/2
⇒ 2x = 3*2
⇒ 2x = 6
⇒ x = 6/2
⇒ x = 3
So, he brought 3 watermelons to the town.
Answer.
Let the total number of watermelons brought to town by the man be x
He sold 1/2 more 1/2 of what he brought = 1/2 more than 1/2 of x
Number of watermelons left with him = 1
Now, according to the question.
⇒ x - (1/2 of x + 1/2) = 1
⇒ x/1 - x/2 - 1/2 = 1
⇒ x/2 = 1 + 1/2
⇒ x/2 = 3/2
⇒ 2x = 3*2
⇒ 2x = 6
⇒ x = 6/2
⇒ x = 3
So, he brought 3 watermelons to the town.
Answer.
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