Math, asked by abdulkarim7284, 1 year ago

A man buys 10 oranges for a rupee and sells 8 oranges for a rupee.What is the profit pwrcentage?

Answers

Answered by Anonymous
22

Solution :-

Cost price of 10 oranges = Rs 1

Cost price of 1 orange = Rs 1/10 = Rs 0.1

Selling price of 8 oranges = Rs 1

Selling price of 1 orange = Rs 1/8 = Rs 0.125

Selling price is greater than the cost price. Therefore, profit.

Profit = S.P - C.P

= Rs (0.125 - 0.1)

= Rs 0.025

Profit percent = (profit × 100)/C.P %

= (0.025 × 100)/0.1 %

= 2.5/0.1 %

= 25 %

Hence,

Profit percentage = 25%

Answered by ram5556
12

Answer:

Cost price of 1 orange is RS 1/10 = RS 0.1.

Cost price of 10 orange is RS 1 .

Selling price of 1 orange is RS 1/8 = RS . 0.125

Selling price of 8 oranges is RS 1.

There is profit so we use formula of profit

Profit = S.P - C.P

RS = (0.125 - 0.1)

Rs = 0.025

Formula of profit percentage :

( Profit × 100 ) / 0.1%

(0.025 × 100 ) /0.1 %

= 25 / 0.1%

= 25 %

So ,

Profit = 25%

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