Question

A man buys 120 oranges at 6 for Rs.5 and 120 more at 1 a rupee, and he sold the whole lot for 4 for 6 rupees. What was his total profit and profit percent.

Answer 1

Cost price of 240 oranges= (5/6 ×120)+(1×120) =Rs 220
Selling price of 240 oranges = 6/4 ×240 = Rs 360
Profit =360-220 = Rs 140
% profit = (140×100)/220 = Rs 700/11

Answer 2

Qᴜᴇsᴛɪᴏɴ :

A man buys 120 oranges at 6 for Rs.5 and 120 more at 1 a rupee, and he sold the whole lot for 4 for 6 rupees. What was his total profit and profit percent ?

Aɴsᴡᴇʀ :

C.P. of 6 oranges = ₹ 5

∴ C.P. of 120 oranges

$= ₹ \dfrac{5}{6} \times 120 = ₹100$

C.P. of 120 oranges at one a rupee = ₹ 120

Total C.P. =$₹100+₹120=₹220$

S.P. of 140 oranges at 4 for 6 rupees $= ₹\dfrac{6}{4} \times 240 = ₹360$

Total profit = S.P. - C.P. = $₹360 - ₹220 = ₹140$

∴ Profit % $= ( \dfrac{Total \: Profit}{Total \: C.p.} \times 100 )\%$

$= ( \dfrac{140}{220} \times 100)\% = \dfrac{140 \times 5}{11} \% = \dfrac{700}{11} \% = 63 \times \dfrac{7}{11} \%$