Math, asked by nishi6057, 6 months ago

A man buys 3 houses. second at double cost and double the price from third to second. He sells the first and second house for a profit of 20%. but on the third it is 10% loss. Overall it happened?​

Answers

Answered by ankitraj63188
0

Answer:

A man buys 3 houses. second at double cost and double the price from third to second. He sells the first and second house for a profit of 20%. but on the third it is 10% loss. Overall it happened?

Answered by halamadrid
1

The man gains an overall profit of 2.85%.

Given:

A man buys three houses, second at double cost and double the price from third to second.

He sells the first and second house for a profit of 20% and incurs a loss of 10% on selling the third house.

To Find:

The overall gain/loss.

Solution:

Let us assume that the man bought the first house at cost of Rs. 100.

Then the cost at which he bought the second house = Rs. 200.

And the cost at which he bought the third house = Rs. 400.

We have been given that he gets 20% profit on each first and second house on selling them

The profit obtained on selling the first house = 20% of 100 = Rs 20

The profit obtained on selling the second house = 20% of 200 = Rs 40.

So the total profit = 20 + 40 = Rs. 60.

Loss incurred on the third house = 10% of 400 = Rs. 40.

∴ Overall gain = 60 - 40 = Rs. 20.

The percentage of gain = (20 *100)/(100 +200 +400) = 2.85%.

Hence, the man gains an overall profit of 2.85%

#SPJ2

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