Math, asked by munna196, 9 months ago

A man buys 4 tables and 5 chairs for 1000 if he sells the tables at 10% profit and chairs 20℅ profit he earns a profit of 120 then what is the cost of one table?​

Answers

Answered by prettystefina11
6

Answer:

Rs 200

Step-by-step explanation:

Let the C.P of each table = x

Let the C.P of each chair = y

4 tables + 5 Chairs = Rs 1000

4x + 5y = 1000  …….Eq(1)

10% profit on tables + 20% profit on chairs = Rs 120

(10/100) * 4x + (20/100) * 5y = 120

40x + 100y = 12000

2x + 5y = 600  ……..Eq(2)

Solving Eq(1) & Eq(2);

4x + 5y = 1000

2x + 5y = 600

(-)  (-)      (-)

———————
2x = 400

=> x = 200

Therefore, the cost of 1 table = Rs x = Rs 200

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