Question

A man buys 6 dozen oranges for Rs. 10.80.12 oranges are found rotten and the rest are sold at five for a rupee. Find his gain or loss per cent.
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Answer 1

A man buy 6 dozen oranges for Rs. 10.80. In which 12 oranges are found rotten.

12 oranges are rotten means, 1 dozen organes are rotten.

(As 1 dozen orange = 12 orange)

So,

Remaining orange = 5 dozen

=> 5 × 12 = 60 oranges

It is also said in question that remaining oranges are sold at five for one rupee.

Selling price of 1 orange = Rs. 1/5

And we have remaining oranges = 60

So, selling price of 60 oranges = Rs. 1/5 × 60

=> Rs. 12

So,

Profit of man = 12 - 10.80

=> Rs. 1.2

According to question, we have to find the profit or loss percent of the man.

So,

Profit % = Profit/Cost price × 100

=> 1.2/10.80 × 100

=> 0.1111 × 100

=> 11.11%

∴ The man gain 11.11%

Answer 2

ANSWER:-

Given:

A man buys 6 dozen oranges for Rs.10.80. 12 oranges are found rotten and the rest are sold at Rs.5.

To find:

Find his gain or loss percent.

Solution:

A man buys 6 dozen oranges for Rs.10.80. &

12 oranges means 1 dozen found rotten.

So,

5 dozen oranges cost him Rs.10.80

Therefore,

Remaining oranges;

5 dozen = 5×12= 60 oranges

Given that the remaining oranges are sold at 5 oranges for Rs.1.

Therefore,

Selling price,(S.P.) of 1 oranges= Rs.1/5

S.P of remaining 60 oranges;

=) 60× 1/5

=) Rs.12

Now,

Profit= S.P. - C.P

=) Rs.(12 - 10.80)

=) Rs.1.2

We know that Profit%,

$= > \frac{Profit}{C.P} \times 100 \\ \\ = > \frac{1.2}{10.80} \times 100 \\ \\ = > \frac{120 \times 100}{1080} \\ \\ = > \frac{1200}{108} \\ \\ = > 11.11\%$

Gain= 1.2 rupees.

Gain% = 11.11%

Hope it helps ☺️