Math, asked by levikunaal8494, 11 months ago

A man buys a box of fruits containing 286 fruits. Out of these, 1/2 of the fruits are apples and rest are pears. 4/13 of the pears are rotten. He sells the good pears at Rs 4 each. How much money does he receive on selling good pears?

Answers

Answered by JinKazama1
13

Answer: ₹ 396

Step-by-step explanation:

We have,

1) Total no. of fruits =286.

Fruits consists of apples and pears. Since, 1/2 of the fruits are apples.

Remaining 1/2 must be pears .

So, 1/2 of 246 are pears.

=> 1/2 *246= 143 pears.

2) Now, we have given that

4/13 of pears are rotten.

=> (1-4/13) of pears are good.

=> 9/13 of pears are good

=> 9/13 *143 = 99 pears are good.

3) Price of 1 good pear = 4

Price of 99 good pear = 99*4 = ₹396

Hence, Required Price =₹396

Answered by s15999
7

Answer:

Rupees Needed: ₹396

Step-by-step explanation:

We have,

Total no. of fruits =286.

Fruits consists of apples and pears. Since, 1/2 of the fruits are apples.

Remaining 1/2 must be pears.

So, 1/2 of 246 are pears.

=> 1/2 *246= 143 pears.

Now, we have given that

4/13 of pears are rotten.

=> (1-4/13) of pears are good.

=> 9/13 of pears are good

=> 9/13 *143 = 99 pears are good.

Price of 1 good pear = 4

Price of 99 good pear

= 99*4 = 396

Hence, Required Price = ₹396.

Hope it helps!

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