Math, asked by aryangawand101, 9 months ago

A man buys a box of fruits containing 286 fruits .Out of these ½ of the
fruits are apples and the rest are pears. 4/13 of the pears are rotten. He sells
the good pears at ₹ 4 1/11 each. How much money does he receive on selling
the good pears?

Answers

Answered by PrithwiCC
37

Answer:

Total fruit is 286.

No. of apples = 286/2 = 143

No. of pears = 286-143 = 143

No. of rotten pears = 143×(4/13) = 44

No. of good pears = 143-44 = 99

Cost of a good pear is ₹ 4 1/11 i.e 45/11

Money received by selling good pears is 45/11 × 99 = ₹405.

Answered by qwachieve
8

Given:

The fruits in the box are 286 fruits.

Cost of selling one good pear = Rs. 4\frac{1}{11}

To find:

To calculate total money received by man after selling good pears.

Solution:

The total number of fruits is 286.

Total number of apples = ½ of 286 fruits

= ½ × 286 = 143

Total number of pears = 286 – 143 = 143

Total number of rotten pears = (4/13) × 143 = 44

Total number of good pears = 143 – 44 = 99

Cost of selling one good pear = Rs. 4\frac{1}{11}

= Rs. 45/11

Total cost of selling 99 good pears = 99 × (45/11)

= 9 × 45 = Rs. 405

The total money received by the man after selling good pears is Rs. 405.

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