Question

A man buys a car for rs 40000 .Every year it depriciates by 3/4th what is its cost after 3 yrs

Answer 1

cost of car = 40000

rate of depreciation = 3/4

cost of car after 1st  year = 40000 x 3/4

                                           = 30000

cost of car after 2nd year = 30000 x 3/4

                                            = 22500

cost of car after 3rd year =22500 x 3/4

                                            16875

therefore , cost of car after 3 years is 16875 Rs

Answer 2

Concept Introduction: Depreciation is a part of life.

Given:

We have been Given: Cost of the car

$rs.40000$

The cost depreciates

$\frac{3}{4} th \: of \: the \: cost$

every year.

To Find:

We have to Find: Find the cost of the car after

$3 \: yrs$

Solution:

According to the problem, Cost after 1 year,

$\frac{3}{4} \times 40000 = rs.30000$

Cost after 2 years,

$\frac{3}{4} \times 30000 = rs.22500$

Cost after 3 years,

$\frac{3}{4} \times 22500 =rs. 16875$

Final Answer: The cost after 3 years is

$rs.16875$

#SPJ3