Question

a man buys a certain number of of oranges at 20 for rupees 60 and an equal number at 3460 system and sell them at 25 for p60 what is his gain or loss percent​

Answer 1

He buys some oranges , say x oranges , at 20 for 60 Rs

20oranges=60Rs

1orange=60/20Rs=3Rs

xoranges=3xRs

Then he buys equal no. Of oranges = x , at 30 for 60 Rs

30oranges=60Rs

1orange=60/30Rs=2Rs

xoranges=2xRs

Total Cost Price = 3x + 2x = 5x Rs

He mixes two types of oranges and sells them at 25 for 60 Rs

25oranges=60Rs

1orange=(12/5)Rs

He had x+ x = 2x oranges to sell.

2xoranges=2x×(12/5)R=(24x/5)Ruppees

Selling price = ( 24x/5 ) Rs

C.P - S.P = 5x - (24x/5 )

Loss = x/5

Loss

=((x/5)÷5x)∗100

=(1/25)∗100=4

Hope it helps uh....

Nd check ur question one time

Answer 2

Answer:

Above one is right answer i think u should give her the BRAINLIEST answer!!!