Question

A man buys a certain number of oranges at 20 for rs.60 and an equal number at 30 for rs.60 .He mixes them and sells them at 25for rs.60.What is gain or loss percent

Answer 1

His loss perencentage is 4%

Given in the question,

A man buys some oranges , let it be 'x' no. of oranges ,

at 20 for Rs 60

So, Cost Price (C.P) of 20 oranges = Rs 60

∴ C.P. of 1 orange = Rs (60/20) = Rs 3

∴ C.P. of 'x' oranges = Rs 3x

It is also mentioned that,

He buys equal no. of oranges ('x')  at 30 for Rs 60

 So, Cost Price (C.P) of 30 oranges = Rs 60

∴ C.P. of 1 orange = Rs (60/30) = Rs 2

∴ C.P. of 'x' oranges = Rs 2x

Thus, total C.P of 2x no.of oranges = Rs (3x + 2x) = Rs 5x

Then,

He mixes two types of oranges and sells them at 25 for Rs 60

 So, Selling Price (S.P) of 25 oranges = Rs 60

∴ S.P. of 1 orange = Rs (60/25) = Rs 2.40

∴ S.P. of  total '2x' oranges = Rs (2x × 2.40) = Rs 4.80x

Since C.P. of '2x' oranges >  S.P. of '2x' oranges

Loss is incured.

Loss value =

C.P - S.P = Rs (5x - 4.80x )

= Rs 0.20x

 

Loss % = [(Loss value) /  (C.P of total '2x' oranges)] × 100%

= (0.20x / 5x) × 100%

= 4%

Thus, 4% loss is incured.