A man buys a house for Rs. 24,000. He pays Rs. 6,000 in cash and agrees to pay the balance in
annual instalments of Rs. 1000 plus 10% interest on the unpaid amount. Find the total cost
(including interest) of the house.
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Answered by
11
Answer:
Cost price of house =24000
He paid in first =6000
Amount he paid in instalment =24000-6000=18000
Number of instalment 18000/1000=18
Rs. He paid in first installment =1000+18000*10/100=28000
Rs he paid in 2nd installment =1000+17000*10/1000=27000
A.p=2800,27000,26000
Sn=n/2(2a+(n-1)d
S18=18/2(2*2800+(18-1)*-100=35100
Here d=2700-2800=-100
Total amount he paid =35100+6000=41100
Answered by
3
Answer:
Ur answer is
41100
Step-by-step explanation:
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