A man buys a number of golf balls for $6 if he had paid 50 cents less for each he could have bought six more for $6 how many balls did he buy
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Let x be the number of golf balls.
The total cost is $6.00
Since total cost=(x)⋅(cost per ball), the cost per golf ball (CPC) is
$6.00
x
. He pays $0.50 less for each to get six more than his initial.
(CPC−$0.50)⋅(x+6)
(
6
x
−0.5)(x+6)
(
6
x
−
0.5x
x
)(x+6)
(
6−0.5x
x
)(x+6)
x⋅(
6−0.5x
x
)(x+6)
(6−0.5x)(x+6)
6x+36−0.5
x
2
−3x
36−0.5
x
2
+3x
36−0.5
x
2
−3x
−0.5
x
2
−3x+36
=$6.00
=6
=6
=6
=6⋅x
=6x
=6x
=6x
=0
=0
To get rid of x in denom
Quadratic formula
x
x
x
x
=
−(−3)±
(−3
)
2
−4(−0.5)(36)
−
−
−
−
−
−
−
−
−
−
−
−
−
−
−
−
√
2(−0.5)
=
3±
81
−
−
√
−1
=−1(3±9)
=−12 or x=6
Reject x=−12. He bought 6 balls
Hope this question's answer are helpful
And press the point of thanks
And please bainalest
The total cost is $6.00
Since total cost=(x)⋅(cost per ball), the cost per golf ball (CPC) is
$6.00
x
. He pays $0.50 less for each to get six more than his initial.
(CPC−$0.50)⋅(x+6)
(
6
x
−0.5)(x+6)
(
6
x
−
0.5x
x
)(x+6)
(
6−0.5x
x
)(x+6)
x⋅(
6−0.5x
x
)(x+6)
(6−0.5x)(x+6)
6x+36−0.5
x
2
−3x
36−0.5
x
2
+3x
36−0.5
x
2
−3x
−0.5
x
2
−3x+36
=$6.00
=6
=6
=6
=6⋅x
=6x
=6x
=6x
=0
=0
To get rid of x in denom
Quadratic formula
x
x
x
x
=
−(−3)±
(−3
)
2
−4(−0.5)(36)
−
−
−
−
−
−
−
−
−
−
−
−
−
−
−
−
√
2(−0.5)
=
3±
81
−
−
√
−1
=−1(3±9)
=−12 or x=6
Reject x=−12. He bought 6 balls
Hope this question's answer are helpful
And press the point of thanks
And please bainalest
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