Question

a man buys a plot of agricultural land for 360000. he sells one third of it at a loss of 20%and two fifth at a gain of 25% at what price must he sell the remaining field so as to make an overall profit of 10%?

Answer 1

Cost =  Rs 3, 60, 000.

cost of 1/3 of the plot = Rs 1,20,000.

loss due to its sale = 20% = Rs 24,000.

cost of the second 1/3 of the plot = Rs 1,20,000

Profit due to its sale = 25% = Rs 30,000.

Net profit to be gained on the overall sales = 10%  =  Rs 36, 000.

 

Profit to be gained from the sale of third part = Rs 36,000 - 30, 000 + 24,000

       = Rs 30,000

So Sale price for the last 1/3 of the plot = Rs 1,20, 000 + Rs 30, 000

       = Rs 1, 50, 000.

Answer 2

Solution:

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C.P. of land = Rs 360000

Let us proceed ACQ

First Sold = 1/3 of 360000 = 120000 .....(i)

Loss = 20%

S.P. = 80% of 120000

S.P. = 96000 ......(i)

second sold = 2/5 of 360000 = 14.4000 .

Gain = 25%

S.P. = 125 % of 144000

S.P. = 180000 ......(ii)

Total sold =120000+144000

= 264000

Remaining part = 360000 - 264000 = 96000

Also remaining field is to be sold at a profit of 10% on the whole 

10 % on the whole = 110% of 360000 = 396000

Total S.P. = 96000 + 180000 = 276000

Remaining part should be sold for Rs = 396000 - 276000 = 120000

C.P.  = 96000

S.P. = 120000

Profit = 24000

Profit% = (24000/96000) x 100 = 25

So, the remaining part should be sold at a profit of 25% 

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