A man buys a plot of land at 3,60,000. He sells one third of the plot at a loss of 20%. Again, he sells two -thirds of plot left at a profit of 25%. At what price should he sell the remaining plot in order to get a profit of 10% on the whole ?
Answers
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Answer:
100000
Step-by-step explanation:
Given cost price of land = 3,60,000.
(i)
Given, overall profit = 10%.
Selling price of the whole part = CP * (100 + gain%)/100
= 360000 * (100 + 10)/100
= 3600 * 110
= 396000.
(i)
Cost price of (1/3)rd of plot = (1/3) * 360000
= 120000.
Loss incurred = 20%.
We know that Selling price = {(100 - Loss%/100} * Cost price
= {(100 - 20/100} * 120000
= (80/100) * 120000
= 96000.
(ii)
Given that (2/3)rd of the plot left at the profit of 25%.
⇒ (2/3) * (1 - 1/3)
⇒ (2/3) * (2/3)
⇒ 4/9 part of initial area.
So,cost price of (4/9) part of initial area = 360000 * (4/9)
= 160000
Selling price = CP * {(100 + Gain%)/100}
= 160000[100 + 25/100]
= 160000[125/100]
= 200000
(iii)
Cost price of plot left = 360000 * (1 - 1/3 * 4/9)
= 80000
(iv)
⇒ Selling price of remaining land = 390000 - (200000 + 96000)
= 396000 - 296000
= 100000.
Hope it's help you.