Question

A man buys a plot of land at ₹360000. He sells one third of the plot at a loss of 20%. Again he sells two thirds of the plot left at a profit of 25%. At what price should he sell the remaining plot in order to get a profit of 10% on the whole?

Answer 1

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The last part of the land should be sold at 150000rs

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The total price of the land is 360000.

For the first 1/3 part he should get

$\frac{1}{3}$x 360000= 120000rs.

But he sells it at a loss of 20%

The amount of loss is →

$\frac{20}{100}$x120000= 24000rs

Therefore, the amount at which the farmer sold 1/3 of land is →

120000-24000= 96000

Similarly, the next 1/3 of the land was sold at ab amount of

120000+ 25%.

profit(amount)=120000 + 30000=150000rs

To get a total profit of 10% the amount at which the total land should be sold is →

360000+10%profit(amount)= 360000+36000=396000

So the total amount at which he should sell all the three parts should be 396000rs

Therefore,96000+150000+x=396000

Therefore,96000+150000+x=396000

(here x is equal to the amount at which the last 1/3 part of the land should be sold)

Now, 246000+x=396000

. x= 396000-246000= 150000rs.

Therefore the last part of the land should be sold at 150000rs