A man buys a plot of land at ₹360000.he sells one third of the plot at a loss of 20% .again he sells two thirds of the plot left at a profit of 25%.At what price should he sell the remaining plot in order to get a profit of 10% on the whole?
Answers
He sold 1/3 of the property which means property worth of 1/3 × 360000= 120000Rs
Loss - 20%.
So loss = 120000 ×20/100= 24000Rs.
SP= 120000-24000= 96000Rs.
Property worth of 360000-120000=
240000 is left.
Now again 2/3 of property means property worth of 2/3 × 240000 = 160000Rs is sold
Gain= 25%
So gain = 160000 × 25/100= 40000Rs.
SP= 160000+40000=200000Rs
[ Total property = 360000
Gain= 10%
Gain= 360000 ×10/100= 36000
SP= 360000+36000= 396000Rs ]
Property left = 240000-160000=80000Rs
Total sold worth = 96000+200000=296000Rs.
SP = 396000-296000= 100000
that mean if he sell his remaining property at 100000 Rs he will incur a profit of 10%.
Hope it helps.
The last part of the land should be sold at 150000rs
The total price of the land is 360000.
For the first 1/3 part he should get
x 360000= 120000rs.
But he sells it at a loss of 20%
The amount of loss is →
x120000= 24000rs
Therefore, the amount at which the farmer sold 1/3 of land is →
120000-24000= 96000
Similarly, the next 1/3 of the land was sold at ab amount of
120000+ 25%.
profit(amount)=120000 + 30000=150000rs
To get a total profit of 10% the amount at which the total land should be sold is →
360000+10%profit(amount)= 360000+36000=396000
So the total amount at which he should sell all the three parts should be 396000rs
Therefore,96000+150000+x=396000
Therefore,96000+150000+x=396000
(here x is equal to the amount at which the last 1/3 part of the land should be sold)
Now, 246000+x=396000
. x= 396000-246000= 150000rs.
Therefore the last part of the land should be sold at 150000rs.