a man buys a plot of land at rupees 360000 .he sells one third of the plot at a loss of 20 percent . again ,he sells two thirds of the plot left at a profit of 25 percent.at what price should he sell the remaining plot in order to get a profit of 10 percent on the whole
Answers
Step-by-step explanation:
cost of 1/3 of the plot = Rs 1,20,000. loss due to its sale = 20% = Rs 24,000. Profit due to its sale = 25% = Rs 30,000. Net profit to be gained on the overall sales = 10% = Rs 36, 000
1/3 of plot,i.e., Rs.1,20,000 sold out for a loss of 20%. Hence selling price = 120000 - [ 120000×(20/100) ] = Rs. 96000 ..........(1)
2/3 of left plot area = [ 1 - (1/3) ]×(2/3) = 4/9 part of initial plot area
cost value of 4/9 plot area = 360000 × (4/9) = Rs. 1,60,000
if 4/9 part of plot is sold for 25% profit, then selling price = 160000 + [ 160000 × (25/100) ] = Rs. 200000 .....................(2)
cost value of left out plot = [ 1 - (1/3) - (4/9) ]×360000 = Rs.80000
total selling price till now = Rs. ( 96000 + 200000 ) = Rs. 2,96,000
overall selling price for the profit of 10% = 360000 + [ 360000×(10/100) ] = Rs. 3,96,000
Hence the left out plot has to be sold for Rs. ( 3,96,000 - 2,96,000) = Rs. 1,00,000