Question

A man buys a plot of land for 72000. He sells
one-third of the land at a loss of 20% and two-
fifth at a gain of 25%. At what price must he
sell the remaining land so as to make an overall
profit of 10%?​

Answer 1

Answer:

Given cost of the land = 72000

(1)

Given that he sells 1/3 of the land = (1/3) * 72000 = (1/3) * 72000

= 24000

We know selling price = 100 - loss%)/100] * CP

= ( 80 * 24000)/100

= 19200

(ii)

Given,that he sells 2/5 of the land = (2/5) * 72000

= 2 * 14400

= 28800

He gain = 25%

We know that selling price = [(100 + Gain%)/100] * CP

= (125 * 28800)/100

= 36000

(iii)

given overall profit it is 10 %

Now,profit = 110 % of 72000

= (10/100) * 72000

= 7200

Hence,the total selling price should be 72000 + 7200 = 79200

So,the total selling price of two parts of land sold = 36000 +19200 = 55200

Hence selling price of remaining land = 79200 - 55200

→24000

Therefore,selling price of remaining land = 24000.

Hope it helps.

Mark as brainliest.

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