Question

A man buys a plot of land for Rs. 360000. He sells one third of the plot at a loss of 20%. Again, he sells two -thirds of the plot left at a profit of 25%. At what price should he sell the remaining plot in order to get a profit of 10% on the whole?

Answer 1

The total price of the land is 360000.
For the first 1/3 part he should get
1/3 x 360000= 120000rs.
But he sells it at a loss of 20%
The amount of loss is
20/100 x120000= 24000
Therefore, the amount at which the farmer sold 1/3 of land is
120000-24000= 96000

Similarly, the next 1/3 of the land was sold at ab amount of
120000+ 25% profit(amount)=120000 + 30000=150000rs

To get a total profit of 10% the amount at which the total land should be sold is
360000+10%profit(amount)= 360000+36000=396000

So the total amount at which he should sell all the three parts should be 396000rs
Therefore, 96000+150000+x=396000
(here x is equal to the amount at which the last 1/3 part of the land should be sold)
Now, 246000+x=396000
. x= 396000-246000= 150000rs.
Therefore the last part of the land should be sold at 150000rs