Math, asked by nikhil141, 1 year ago

a man buys a plot of land for Rs 72000 he sell one third of the land at a loss of 20% and two fifth at a gain of 25% at what price must he sell the remaing land so as to make an overall 10%

Answers

Answered by Abhirup1
118
72000*1/3=24000*(100-20)%=19200.
2/5*72000=28800*125%=36000.he have to make a profit of 72000* 10%=7200, 72000+
7200- ( 19200+36000)=24000. so remaining
land sold at Rupees 24000.
Answered by TooFree
118

Cost of the land = Rs 72,000


Find the expected selling price to gain 10%:

10% gain = 10% x 72,000 = 0.1 x 72,000 = Rs 7,200

Expected selling price = 72000 + 7200 = Rs 79,200


Find the Selling Price of the 1/3 of the land sold at 20% loss:

cost of 1/3 of the land = 1/3 x 72,000 = Rs 24,000

20% loss = 20% x 24,000 = 0.2 x 24000 = Rs 4800

Selling Price = 24,000 - 4800 = Rs 19,200


Find the selling price of the 2/5 land that gains 25%:

Cost of the 2/5 land = 2/5 x 72000 = Rs 28,800

25% gain = 25% x 28,800 = 0.25 x 28800 = Rs 7200

Selling Price = 28,800 + 7200 = Rs 36,000


Find the selling price of the remaining land:

Selling Price = 79,200 - 19,200 - 36,000 = Rs 24,000


Answer: The selling price of the remaining land is Rs 24,000


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