Question

A man buys a plot of land for rs 72000. He sells 1/3rd of the land at a loss of 20% and 2/5th at a gain of 25%. At what price must he sell the remaining land so as to make an overall profit of 10%?
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WITH EXPLANATION!!
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ITS URGENT!!
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Answer 1

72000*1/3=24000*(100-20)%=19200.
2/5*72000=28800*125%=36000.
he have to make a profit of 72000* 10%=7200, 72000+
7200- ( 19200+36000)=24000. so remaining
land sold at Rupees 24000.

I hope it help you

Answer 2

Given, cost price of the land = 72000.

(i)

Given that he sells 1/3 of the land = (1/3) * 72000

                                     = (1/3) * 72000

                                     = 24000.

Loss = 20%.

We know that Selling price = [(100 - loss%)/100] * CP

                                             = (80 * 24000)/100

                                             = 19200.

(ii)

Given that he sells 2/5 of the land = (2/5) * 72000

                                                         = 2 * 14400

                                                         = 28800.

Gain = 25%.

We know that Selling price = [(100 + Gain%)/100] * CP

                                             = (125 * 28800)/100

                                             = 36000.

(iii)

Given overall profit is 10%.

Now, Profit = 110% of 72000

                   = (10/100) * 72000

                   = 7200.

Hence, the total selling price should be 72000 + 7200 = 79200

So, the total selling price of two parts of land sold = 36000 + 19200 = 55200.

Hence, Selling price of remaining land = 79200 - 55200

⇒ 24000.

Therefore, Selling price of the remaining land = 24000.

Hope this helps!